Aptitude Test Preparation

Aptitude-Test-Tricks- & -Shortcuts

 

PROFIT AND LOSS

Q 1. A PERSON GOT 5% LOSS BY SELLING AN ARTICLE FOR

RS 1045 AT WHAT PRICE SHOULD BE THE ARTICLE BE SOLD TO EARN 5% PROFIT?

SOLUTION

=(1045/95)*105

=1155

Profit-and-Loss-questionsQ 2. IF THE CP OF 12 ARTICLE IS EQUAL TO SP OF 9 ARTICLE

FIND THE GAIN OR LOSS % ?

SOLUTION

=12-9  = 3

=(3/9)*100 = 33.33%

Q 3. A VENDOR BOUGHT BANANAS AT 6 FOR RS  10 AND SOLD THEM AT 4  FOR RS 6. FIND HIS GAIN OR LOSS % ?

SOLUTION

= (6*6)-(10*4)

=  (-4/40)*100

=  -10%

=10 % LOSS

Q 4. A PERSON SOLD AN ARTICLE AT 12% PROFIT IF HE SOLD

THAT ARTICLE AT 3.60 MORE . HE COULD HAVE GAIN 18 %.

FIND OUT CP OF THE ARTICLE  ?

SOLUTION

= (3.60/6)*100

=RS 60

 

Percentage-tricksSIMPLE INTEREST

Q 1. A CERTAIN SUM OF MONEY DOUBLES ITSELF IN 8 YEARS

FIND OUT THE RATE OF INTEREST ?

 

SOLUTION

 

=R*T = 100(N-1)

=R*8=100(2-1)

= R=100/8

R=12.5%

 

 

Q 2. A SUM OF MONEY DOUBLES ITSELF IN 7 YEARS . IN HOW MANY YEARS IT HAS BEEN FOUR TIMES ?

 

SOLUTION

 

  • = R*T=100(N-1)

=R*7=100

R=100/7

 

  • =(100/7)*T=100(4-1)

T=7*3

T=21 YEARS

 

Q 3. FIND OUT THE DIFFERENCE BETWEEN CI. AND SI.WHEN

PRINCIPAL IS 5000 , R=10% PER ANNUM TIME =2 YEARS ?

 

 

SOLUTION

 

= CI.-SI. = P(R/100)^2

 

=5000(10/100)^2

 

=RS 50

 

SPEED TIME AND DISTANCEspeed-time-distance

 

Q 1. PETER CAN COVER A CERTAIN DISTANCE IN 1 HOUR 24 MIN . BY  COVERING TWO  THIRD  OF THE  DISTANCE  AT  4 KMPH  AND  THE  REST  AT  5  KMPH .  FIND  THE   TOTAL DISTANCE ?

 

SOLUTION

 

LET TOTAL DISTANCE BE X KM. THEN

 

= ((2/3)X)/4+((1/3)X)/5 =7/5 = 6 KM

 

 

 

Q 2. IF A MAN WALKS AT THE RATE  OF 5 KM/HR , HE MISS A

TRAIN BY 7 MIN . HOWEVER IF HE WALKS AT THE RATE  OF  6  KMPH,  HE  REACHES  THE  STATION  5 MIN  BEFORE  THE ARRIVAL OF THE TRAIN . FIND THE DISTANCE COVERED BY

HIM TO REACH THE STATION ?

 

SOLUTION

 

LET REQUIRED DISTANCE BE X KM

DIFF.  IN  TIMES  TAKEN  AT  TWO

SPEEDS  =  12  MIN =  1/5  HOUR

 

= (X/5) – (X/6) = 1/5

 

X = 6KM

 

 

 

CLOCKAptitude-Questions-related-to-Clock

 

Q 1. FIND THE ANGLE BETWEEN THE HOUR HAND AND MINUTE  HAND OF A CLOCK WHEN TIME IS 3:25 ?

 

 

SOLUTION

 

ANGLE= 11/2  MIN – 30 HOUR

 

=(11/2)*25 – 30*(3)

 

= 47.5 DEGREE

 

Q 2. AT WHAT TIME BETWEEN 2 AND 3 O CLOCK  WILL HANDS OF A CLOCK BE TOGETHER ?

 

 

SOLUTION

 

= (60/55)*10

=10  10/11 MIN

 

 

TRAINS

 

Q 1.  HOW LONG DOES A TRAIN 110 METER LONG RUNNING AT THE SPEED OF 72 KMPH TAKE TO CROSS A BRIDGE 132 METER IN LENGTH ?

SOLUTION

 

TOTAL  LENGTH = 110+132

= 242 METER

 

SPEED                   72*(5/18)= 20 M/SEC

 

TIME                    = 242*(18/72*5)

 

= 12.1 SEC

Q 2. A TRAIN 150 M LONG IS RUNNING WITH A SPEED OF 68

KMPH . IN WHAT TIME WILL IT PASS A MAN WHO IS RUNNING AT 8 KMPH IN THE SAME DIRECTION IN WHICH THE TRAIN IS GOING ?

 

 

SOLUTION

 

RELATIVE SPEED = 68-8 = 60 KMPH

=(60*5/18)= 50/3 M/SEC

 

TIME                        = 150*3/50

= 9 SEC

 

 

 

CHAIN RULE

 

Q 1 . IF 36 MEN CAN DO A PIECE OF WORK IN 25 HOURS IN HOW MANY HOURS WILL 15 MEN DO IT ?

 

SOLUTION

 

X= (36*25)/15

 

= 60- HOURS

 

 

 

Q 2.  IF THE WAGES OF 6 MEN FOR  15 DAYS BE RS 2100, FIND THE WAGES OF 9 MEN FOR 12 DAYS ?

 

SOLUTION

X=  (9*12*2100)/(6*15)

 

= RS 2520

 

 

 

ALLIGATION OF MIXTURE

 

 

Q 1. IN WHAT RATIO MUST RICE AT RS 9.30 PER KG BE MIXED WITH  RICE  AT RS 10.80 PER KG SO THAT THE MIXTURE BE WORTH RS 10 PER KG ?

 

SOLUTION

 

= (10.8 – 10)/(10 – 9.3)

= 8:7

 

 

Q 2 . IN WHAT RATIO MUST WATER BE MIXED WITH MILK TO GAIN  20% BY SELLING THE MIXTURE AT COST PRICE ?

 

SOLUTION

 

= (120-100)/(100-0)

= 1:5

 

 

Q 3. A DISHONEST  MILK MAN PROFESSES TO SELL HIS MILK AT COST PRICE BUT HE MIXES IT WITH WATER AND THERE BY GAINS 25 % . THE PERCENTAGE OF WATER IN THE MIXTURE IS ?

 

SOLUTION

 

= (125- 100)/(100-0)

= 25/100

= 1:4

 

HENCE % OF WATER IN MIXTURE = (1/5)*100

= 20%

 

“All the Best for your Interviews”

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